solution
Primary to secondary turns, N1 / N2 = 5

(i) Average current, Idc =

(ii) The peak inverse voltage is equal to the maximum secondary voltage, i.e
PIV = 65V
(iii)

Primary to secondary turns, N1 / N2 = 5

(i) Average current, Idc =

(ii) The peak inverse voltage is equal to the maximum secondary voltage, i.e
PIV = 65V
(iii)

Licensed under the Creative Commons Attribution Share Alike License 4.0