solution
Primary to secondary turns, N1 / N2 = 5
(i) Average current, Idc =
(ii) The peak inverse voltage is equal to the maximum secondary voltage, i.e
PIV = 65V
(iii)
Primary to secondary turns, N1 / N2 = 5
(i) Average current, Idc =
(ii) The peak inverse voltage is equal to the maximum secondary voltage, i.e
PIV = 65V
(iii)
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